I need to solve following integral: $I_{n}=\int_{-1}^{1}\frac{1}{x}P_{n}(x)P_{n-1}(x)dx$. I have hint that following equation needs to be used: $(n+1)I_{n+1}+nI_{n}=2$. Does anyone have idea how to proceed?
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Can you prove that recursion formula that is given as a hint? – uniquesolution Jun 12 '20 at 16:26
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What have you tried ? – user577215664 Jun 12 '20 at 16:29
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Then solve for the sequence $u_n=nI_n$ – EDX Jun 12 '20 at 16:48
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First of all, it is easy to see that $I_1 = 2$. Then, after proving the given recurrence relation, you can see that: $I_2 =0$, $I_3=\frac{2}{3}$, $I_4=0$, $I_5=\frac{2}{5}$, ... It is clear that you have ($n \geq 1$): $$I_{2n} =0$$ and $$I_{2n-1} = \frac{2}{2n-1}$$
Manuel Norman
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