If $g(x) = f(\sin(2x))$ and $g'(0) = 1$ then what is $f'(0)$?

Question

Comments are not for extended discussion; this conversation has been moved to chat. — Aloizio Macedo, Jun 22 '20 at 19:23

score 2 · Accepted Answer · answered Jun 20 '20 at 18:03

2

Since g is differentiable at $0$
By the chain rule $$ g’(0)= f’(0) 2 cos(0)=1$$ Rearranging we get $f’(0)=1/2$

answered Jun 20 '20 at 18:03

Vivaan Daga

1 Answers1