Prove that determinant of triangular matrix is the product of its diagonal ennltries.

Asked Jul 04 '20 at 03:19

Active Jul 04 '20 at 03:19

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Prove that determinant of triangular matrix is the product of its diagonal entries.

I want to use $\operatorname{'sgn'}$.I know that $\operatorname{det}(A)=\sum\limits_{\sigma}A(1,\sigma1)...A(n,\sigma n)$.Any help.

Thanks in advance.

asked Jul 04 '20 at 03:19

1

See https://math.stackexchange.com/a/3577797 – Minus One-Twelfth Jul 04 '20 at 03:24
Are you familiar with Laplace expansion to calculate the determinant? – paulinho Jul 04 '20 at 03:43
In @ShubhamJohri's link, make sure to scroll past the accepted answer to Maurice P's answer to get an answer using this particular formula. – user804886 Jul 04 '20 at 03:48

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