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Use Baire Category to prove that the upper integral from $0$ to $1$ of any $f:[0,1]\to(0,1]$ is greater than $0$.

Asaf Karagila
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Snake
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1 Answers1

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Hint: Given $n\ge 1$, let $E_n$ be the closure of the set $\{x\in[0,1],f(x)\ge\frac{1}{n}\}$. Apply Baire's category theorem to $\cup_{n=1}^\infty E_n=[0,1]$.

23rd
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