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I have put the fraction into Symbolab which gives some step-by-step explanation on why this os correct, but I am unable to grasp how this is possible.

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    I suggest that you transcribe the step-by-step explanation you have, and then explain how much you understand and where you get stuck or confused. – halrankard Jul 13 '20 at 15:04

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Adding and $+4$ and $-4$ to the numerator, if $x\in \Bbb R \setminus \{1\}$, you have:

$$\frac{4x}{x-1}=\frac{(4x-4)+4}{x-1}=\frac{4x-4}{x-1}+\frac4{x-1}=4\frac{x-1}{x-1}+\frac4{x-1}=4+\frac4{x-1}$$

Sebastiano
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