Is the set of equivalent classes of monotone functions $f:[a,b] \to [0,1]$ compact in $L^2([a,b])$?
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2what do you mean with "the set has compact support"? – Pink Panther Jul 16 '20 at 12:16
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2Can you tell us why it is closed? – Kavi Rama Murthy Jul 16 '20 at 12:19
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2For clarity you should say equivalence classes of monotone functions. – Kavi Rama Murthy Jul 16 '20 at 12:22
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@KaviRamaMurthy. for closeness : https://math.stackexchange.com/a/1570240/795522 – user15958 Jul 16 '20 at 12:36
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1The basic space here is different. – Kavi Rama Murthy Jul 16 '20 at 13:02
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Yes. Let $f_n$ be a sequence of such functions. By the Helly selection theorem, there is a subsequence $f_{n_k}$ converging pointwise to some $f$, which is clearly again monotone. And by dominated convergence this subsequence also converges in $L^2$.
Nate Eldredge
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