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If $G$ and $H$ are divisible groups each of which is isomorphic to a subgroup of the other, then $G$ is isomorphic to $H$.

Here, $G$ and $H$ are abelian groups. Can we assume another adjective rather than divisibility?

t.b.
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Baker
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  • Cyclic. 2) Finitely-generated-and-torsion-free. Surely many others (perhaps "finitely generated" suffices?)
  • – Alon Amit May 08 '11 at 13:47