Assuming that beer contains 5% alcohol while vodka contains 40%
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1https://math.stackexchange.com/questions/3783139/new-mix-of-drink-with-different-strong-alcohol – Aug 08 '20 at 00:13
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3Does this answer your question? New mix of drink with different strong alcohol In the meantime, please show what you have tried to get an answer. – Toby Mak Aug 08 '20 at 00:18
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So it would be a equation like x0,4 + 4000,05 = 0,12? – William Aug 08 '20 at 00:23
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If that is the case is the answer 49.7ml correct? – William Aug 08 '20 at 00:27
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@TobyMak In the meanwhile I would suggest to take a bomb shot. – Michael Hoppe Aug 08 '20 at 19:03
1 Answers
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Let $x$ be the amount of vodka to add.
The amount of liquid in the mixture is $400+x$.
As the liquid is $12\%$ alcohol, so he amount of alcohol in the liquid is $0.12 (400 + x)$.
The beer is $5%$ alcohol so the amount of alcohol from the beer is $0.05\times 400$.
And the vodka is $40\%$ alcohol so the amount of alcohol from the vodka is $0.4\times x$.
So the total amount of alcohol in the liquid is $0.05 \times 400 + 0.4 x$.
And the total amount of alcohol in the liquid is $0.12(400+x)$.
So.......
fleablood
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Oh i almost got it right.Got it wrong about the amount of alcohol.Thanks fleablood. – William Aug 08 '20 at 00:30
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That's not quite exact as there will occur a volume contraction if water and alcohol are mixed. For example, mixing 50 ml ethanol and 50 ml water will give a total volume of 96 ml. – Michael Hoppe Aug 08 '20 at 13:24
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1Pfft.... real worlds only important to those who choose to live in it. – fleablood Aug 08 '20 at 15:38