Set C is symmetric difference of set A’s intersection of set B. therefore, is a subset of set A. the result is unioned with set B.
Asked
Active
Viewed 66 times
0
-
The symmetric difference of $C$ with intersection of $A$ and $B$, is a subset of $A$ and $B$'s union. – cr001 Aug 14 '20 at 14:53
-
I need the equation of this. – Nichole Reed Aug 14 '20 at 14:59
-
This statement is false for $A=B={1}$, $C={1,2}$, the LHS becomes ${2}$; the RHS becomes ${1}$. – Henno Brandsma Aug 14 '20 at 16:53
-
"What is the logical statement" is a very unclear question. Clarify? statement about what? $C \Delta (A \cap B) \subseteq A \cup B$ is already a statement. – Henno Brandsma Aug 14 '20 at 16:55
1 Answers
0
$\forall x.(x\in A \land x\in B \land x\notin C \lor (x\notin A\lor x\notin B)\land x \in C)\implies x\in A\lor x\in B$
cr001
- 12,598
-
-
To translate in English, "for all $x$, if $x$ is in either ($A$ and $B$'s intersection) or $C$ exclusively, then $x$ is in ($A$ and $B$'s union)". This is what the original statement means. – cr001 Aug 14 '20 at 15:18
-
You are a blessing I have been struggling for 2 weeks and couldn't get no help. – Nichole Reed Aug 14 '20 at 15:21
-
You are welcome. One way to get quick help is to ask your professor directly. – cr001 Aug 14 '20 at 15:25
-
I did, I didn't understand what she said, I also asked 5 math teachers with no success. – Nichole Reed Aug 14 '20 at 15:31
-
That's really sad. I think you should communicate more to understand what your professor says. After all she is the one that gives all the exams and homeworks. – cr001 Aug 14 '20 at 15:36