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Set C is a subset of A union B. 1 is in set A, then also a union with B gives {1, 2, 3, 4, 5, 6} We know – A U B is { x | x є A) v (x є B) C ⊑ is a subset of A U B which means every element in A U B is also C. Ɐ є { x | x є A) v (x є B) Is this correct?

Kelvin Lois
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Nichole Reed
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  • Not sure what you're asking but $C \subseteq A\cup B$ means any element $x \in C$ is in $A$ or $B$. – Kelvin Lois Aug 14 '20 at 15:28
  • write in logical symbols (using Ɐ, ﾖ, etc.) And then showing that the resulting formulas are equivalent. – Nichole Reed Aug 14 '20 at 15:30
  • @Nichole Reed every element in C will be in AUB – Namburu Karthik Aug 14 '20 at 15:30
  • It is a little challenging to read your OP with as is since you don't mention what $A$, $B$ area or what $C$ is. Although that may not be important, I can't se what is the relevance of $1$, or ${1,2,3,4,5,6}$ in your conclusion. Now, If I understood correctly, your conclusion was that every element of $A\cup B$ is in $C$. That is false.

    But here is my stab at it, replacing quantifier and logical symbols with English words.

    $$A\cup B={x:x\in A\quad\text{or}\quad x\in B}$$

    $C\subset A\cup B$ means that $$\text{for all} x, \quad x\in C\quad \text{implies}\quad x\in A\cup B$$

     – Mittens Aug 14 '20 at 15:31
  • The original question is C\ a⊆b write in logical symbols (using Ɐ, ﾖ, etc.) And then showing that the resulting formulas are equivalent. – Nichole Reed Aug 14 '20 at 15:32
  • See here to learn how to write with MathJax. I just rollback your question to the original one. – Kelvin Lois Aug 14 '20 at 15:33
  • Oliver Diaz, How did you get that? – Nichole Reed Aug 14 '20 at 15:38

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