What is the best/most correct way to represent the logarithm of a number? Example: $$-3 \log2+5 \log175+2 \log7429+3 \log34749$$
- Just leave it the way it was calculated $$-3 \log2+5 \log175+2 \log7429+3 \log34749$$
- As a single $\log$ $$\log \biggl(\frac{380082516906650443140753544921875}{8}\biggl)$$
- Two logarithms for the positive and the negative part (in case they both exist. Otherwise use the above) $$\log 380082516906650443140753544921875 - \log 8$$
- As a sum of logarithms of prime numbers $$-3 \log2 + 15 \log3 + 10 \log5 + 5 \log7 + 3 \log11 + 3 \log13 + 2 \log17 + 2 \log19 + 2 \log23$$
- As a sum of logarithms with different coefficients ($a\log b$ means $b$ is the product of the primes numbers with exponent $a$ in the prime factorization) $$-3 \log2 + 15 \log3 + 10 \log5 + 5 \log7 + 3 \log143 + 2 \log7429$$
Is any of these the best way? Does it matter?
EDIT: I got curious because this number is really big. Obviously if the number is smaller the 2nd or 3rd options are fine