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In demorgan's theorem we were taught on three steps to achieve the answer

First step is to not all inputs

If the given is $ab$ then $(a)'(b)'$

Second step is to change the sign opposite to the current sign. From or to and and vice versa.

$(a)'+(b)'$

And lastly, simply not the final answer.

$((a)'+(b)')'$

If this is wrong please tell me. If not please proceed below.

So for exmaple the given is:

$ab + c$

Will I simply not the first term or not a and not b

$(ab)'$ or $((a)'(b)')$ ?

Mendrix Manlangit
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1 Answers1

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the fast answer is that you right (ab)'. if things like that confuse you the easiest way (at least for me) is to set e=ab and now you got e+c which you know to equivalent to (e'c')' and than you can exchange back to $$ (e'c')'=((ab)'c')'=((a'+b')c')'$$

תום ווקנין
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