I have this equivalence relation (this one is proven already):
$(a,b) R (c,d) ⇔ a + d = b + c$
and now I need to show that for $(a,b),(c,d),(e,f) ∈ ℕ x ℕ$:
$(a,b)R(c,d) ⇒ (a+e,b+f)R(c+e,d+f)$
What I did:
$a+d = b+c$
add f:
$⇒ a+d+f = b+c+f$
add e:
$⇒ a+d+f+e = b+c+f+e$
⇒$a+e+d+f = b+f+c+e$
⇒$(a+e)+(d+f) = (b+f)+(c+e)$
Am I allowed to just add e and f on both sides? If not, how should I get started instead?