i can't find rigorous definition about statistic model. Many authors use the definition below
let suppose to have a probability space
$$(\Omega,\mathcal{F},\mathbb{P})$$
a statistic model is
$$( \{X_i \}_{i \in I_n}, F, \Theta)$$
where $\{X_i \}_{i \in I_n}$ are r.v, $F$ is the set of densities and $\Theta$ is the parametric space.
unfortunately nobody report the domain of r.v., imho all $X_i$ are defined in the same domain $\Omega$ because this would clarify the statement below if $X_i$ are iid with densities $f_i(x_i)$
$$\mathbb{P}(\bigcap_{k=1}^{n}X_{k}^{\leftarrow}(A_k))= \int_{A_1 \times...\times A_n}\prod_{k=1}^{n}f_k(x_k)dx_1...dx_n$$
another perplexity is about the definition of sample random vector $(X_1,...,X_n)$, is:
$$X(\omega_1,...,\omega_n)=(X_1(\omega_1),...,X_n(\omega_n))$$ or what else?
could someone explain me how to formalize all?
@angryavian
my problem is about using rigorously the measure theory in statistic. I give you an example to see if i understand: i would to build a statistic model starting with a probability space $(\Omega,\mathcal{F},\mathbb{P})$ and a single r.v $X: \Omega->\mathbb{R}$ with $f(x|\theta)$ density, and extend it like sequence of coin flip(for simplicity take $n=2$).
i can define on product space $(\Omega^2,\mathcal{F}\otimes\mathcal{F},\mathbb{P}\times\mathbb{P})$ the r.v $X_k(\omega_1,\omega_2)=X(\omega_k), k=1,2$
so using $\mathbb{P}\times\mathbb{P}(A)= \int_{\Omega} \int_{\Omega}\mathbb{1}_{A}(\omega_1,\omega_2)d\mathbb{P}d\mathbb{P}$
i can say that $$\mathbb{P}\times\mathbb{P}((X_1,X_2)^{\leftarrow}(A_1\times A_2))= \int_{\Omega} \int_{\Omega}\mathbb{1}_{A_1\times A_2}(X(\omega_1),X(\omega_2))d\mathbb{P}d\mathbb{P}= \\ \int_{\Omega} \int_{\Omega}\mathbb{1}_{A_1\times A_2}(X(\omega_1),X(\omega_2))d\mathbb{P}d\mathbb{P}=\int_{\Omega}\mathbb{1}_{A_1}(X(\omega_1))d\mathbb{P}*\int_{\Omega}\mathbb{1}_{A_2}(X(\omega_2))d\mathbb{P}$$
i use $\mathbb{1}_{A \times B}(x,y) = \mathbb{1}_A(x) *\mathbb{1}_B(y)$
now $\int_{\Omega}\mathbb{1}_{A_1}(X(\omega_1))d\mathbb{P}=\int_{\Omega} \int_{\Omega}\mathbb{1}_{A_1}(X(\omega_1))d\mathbb{P} d\mathbb{P}= \mathbb{P}\times\mathbb{P}(X_1^{\leftarrow}(A_1)) \\$ the same procedure used for$ X_2$ gives indipendence
in conclusion i can say that my statistic model could be $$\mathbb{P}_{(X_1,X_2)}: \theta \rightarrow \int_{S}f(x_1|\theta)f(x_2|\theta)dx_1 dx_2$$
in fact the distributions of $X_1,X_2$ are the same of $X$ because $$\mathbb{P}\times\mathbb{P}(X_1^{\leftarrow}(A))= \int_{\Omega}\mathbb{1}_A \circ X d\mathbb{P}=\int_A f(x|\theta)dx$$ $\\$ i hope i have expressed all correctly
Introduction to the theory of statistics - McFarlane, Statistical inference - Casella - Berger , Statistical inference based on the likelihood - Azzalini(i use the Italian edition),
e.g they use $X_1,...,X_n$, $(X_1,...,X_n)$ or $T(X_1,...,X_n)$ without specifying much else
– anto_zoolander Sep 26 '20 at 19:26