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This is problem 14 from section 1.2 in the book Matrix Theory Basic Results and Techniques 2nd edition.

If $A B=A+B$ for matrices $A, B,$ show that $A$ and $B$ commute, i.e., $$ A B=A+B \quad \Rightarrow \quad A B=B A $$

The problem appear to be a "simple" problem that we just need to play around with $AB=A+B$. But after a hour of trying, I couldn't figure it out. Any hint will be appreciated.

Sebastiano
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2 Answers2

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Hint: $AB=A+B \implies AB-A-B+I=I \implies (A-I)(B-I)=I$, from here prove that $A-I$ and $B-I$ are inverses of each other (note, you can prove directly from the given equation that they are square matrices). After proving that, write $(B-I)(A-I)=I$ and expand.

Fawkes4494d3
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Rearrange to $(A-1)(B-1)=1$. So these matrices are inverse of one another ... so $(B-1)(A-1)=1$ and the result follows.

Donald Splutterwit
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