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I'm having trouble with this problem and I need help to solve it...

A person has $800$ ft of fencing. He wishes to form a rectangular enclosure and then divide it into three sections by running two lengths of fence parallel to one side. What should the dimensions of the enclosure be in order to maximize the enclosed area?

Air Mike
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Apex Raider
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    I solved your problem. If you want to see my solution, show please your attempts. – Michael Rozenberg Sep 28 '20 at 09:29
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    This is a word problem. Have you managed to write it in a mathematical (algebraic) language, to start with? –  Sep 28 '20 at 09:32
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    You can write some relations between perimeter, that is 800, and area of the rectangle – Lion Heart Sep 28 '20 at 09:32
  • TOTAL FENCING =2L+2B+2L=4L+2B=800
    AREA = LB = L(400-2L)
    =2(200L-L^2)
    =2{100^2-(L-100)^2} maximum area is 2*100^2=20000 ft^2     – Apex Raider Sep 28 '20 at 09:38
  • Looks like you've almost solved it then ... Just for which $L$ will $100^2-(L-100)^2$ be maximal? (And then what is $B$?) –  Sep 28 '20 at 09:40

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