Lets say we have a matrix A = $$ \begin{matrix} -1 & 1\\ 2 & 1\\ \end{matrix} $$
and C = $$ \begin{matrix} 1 & 2\\ -1 & 1\\ \end{matrix} $$
The questions are:
- (a) Find the invertible matrix X such that C = XA and express X as a product of two elementary matrices.
- (b) Using the results in (a), find the invertible matrix N ϵ X2x2 such that A = NC.
So what I know so far is that M would just be the inverse of A multiplied by the C matrix. And I found X to be X= $$ \begin{matrix} -2/3 & -1/3\\ 1/3 & 5/3\\ \end{matrix} $$
But after this, im just lost.
How would I express M as a product of two elementary matrices if reducing X to its RREF would require around 3 elementary row operation?
What does N ∈ M(2x2) supposed to mean?
What i'm thinking of trying to do is to augment a 2x2 identity matrix to the X matrix then perform 1 elementary operation. That will be my two elementary matrix. To illustrate:
$$[\begin{matrix}1 & 0\\0 & 1\\\end{matrix}] *E1 = [\begin{matrix} -2/3 & -1/3\\ 1/3 & 5/3\\ \end{matrix}]$$
But then if i do one elementary operation then multiply the resulting 2x2 identity matrix and the modified X, i don't get X back.
Is this how its supposed to work? The problem specified that I only use two elementary matrices but then if the RREF on the matrix, it would take more than 1 step so i'm not sure how to do this.