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I am trying to understand the simplification of the boolean expression:

A’(BC + AB + BA’)

I was wondering if someone could show me the steps needed to do this. Thank you in advance

dobdobeh alias
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1 Answers1

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First distribute $A'$: $$A'BC+A'AB+A'BA'$$ By idempotence and annihilation this is equal to $$A'BC+A'B$$ Then by absorption on $A'B$ we get the final result as $$A'B$$

Parcly Taxel
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