Could someone please explain what this question is asking? I might be able to solve it by myself by what does it mean by $x^4$? I interpret it as provide a value of $x^4$ given this quadratic so quadratic formula then raise both sides to power $4$ ? There are no real solutions to this quadratic anyway as well so I am confused.
4 Answers
you can start from here $$x^2=3x-6$$ then multiply by $x$ $$x^3=3x^2-6x$$ now put $x^2=3x-6$ it means $$x^3=3(3x+6)-6x=9x+18-6x$$ now you have $x^3$ in terms of x.
can you take over?
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I interpret it as
$x^2 -3x + 6 = 0$ so $x^2 = 3x -6$ so $x^4 = ????$ what?
$x^4 = (x^2)^2 = (3x-6)^2 = 9x^2 -36x + 36$
But we aren't done. Can we get $x^4 = ax + b$ for some $a$ and $b$?
$x^4 = 9x^2 -36x + 36 = 9(3x-6)-36x + 36 = 27x - 54 -36x + 36=-9x -18$
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Your task is to find an equation of the form $$x^4=f(x)$$ where $f$ has the least possible degree, given the relation $x^2-3x+6=0$. Well, we can rearrange this to $x^2=3x-6$, then square both sides to get $x^4=(3x-6)^2=9x^2-36x+36$. Substituting $x^2=3x-6$ again into this gives the final answer as $9(3x-6)-36x+36=-9x-18$.
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$x^2 = 3(x-2) \Rightarrow x^4 = 9(x-2)^2$
$= 9(x^2 - 4x + 4) = 9[3(x-2) - 4x + 4]$
$= 9[3x - 6 - 4x + 4] = 9[-x - 2].$
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$signs around all math expressions, to make the MathJax commands effective. – saulspatz Oct 10 '20 at 05:23