How to simplify the Boolean expression (A'B+C)'(C+A)?

Question

I am trying to solve the following problem:

(A'B+C)'(C+A)

= (AB'+C')(C+A)

= AB'C+AB'A+C'C+C'A

= AB'C+AB'A+0+C'A

= AB'C+AB'+C'A

Than what?

score 1 · Accepted Answer · answered Oct 17 '20 at 13:41

1

You have applied De Morgan incorrectly in the first step... $$(A'B+C)'(C+A)=((A'B)'C')(C+A)$$ $$=(A+B')C'(C+A)=(A+B')C'A=AC'$$

answered Oct 17 '20 at 13:41

Parcly Taxel

score 0 · Answer 2 · answered Oct 17 '20 at 13:37

0

$(A'B+C)' = (A'B)'C' = (A+B')C'$ to begin with.

answered Oct 17 '20 at 13:37

Wuestenfux

1

Did I make a mistake here: (A'B+C)'(C+A) = (AB'+C')(C+A)? Rather shouldn't it be (A'B+C)'(C+A) = (AB'C')(C+A)? – Sakib Arifin Oct 17 '20 at 13:40
Seems like a different formula – Wuestenfux Oct 17 '20 at 13:41

2 Answers2