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Prove that if |, then |, for any , , , ∈ ℕ

So I have, if abc|cd, then abc(k) = cd. I'm very confused on how to continue

1 Answers1

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Hint:

Since $abc\mid cd$ we know that there is some integer $k$ such that $abck = cd$

If we were to multiply both sides by $b$...

Then $ab(bck)=bcd$ and noting that $bck$ is an integer...

JMoravitz
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