Prove that if |, then |, for any , , , ∈ ℕ
So I have, if abc|cd, then abc(k) = cd. I'm very confused on how to continue
Prove that if |, then |, for any , , , ∈ ℕ
So I have, if abc|cd, then abc(k) = cd. I'm very confused on how to continue
Hint:
Since $abc\mid cd$ we know that there is some integer $k$ such that $abck = cd$
If we were to multiply both sides by $b$...
Then $ab(bck)=bcd$ and noting that $bck$ is an integer...