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$(3/4)^{2x-1}= (4/3)^{x-2}$

How do i get the bases to be the same? My teacher just added a $-1$ and everything magically turned to $(3/4)^{2-x}$, How did this happen?

1 Answers1

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$(3/4)^{2x-1}= (4/3)^{x-2}$ and then as Tito mentioned we have $(3/4)^{2x-1}= (3/4)^{-x+2} $ so they have the same base and we should solve the equation for powers: $2x-1=-x+2$ and then $3x = +3$ so $x=1$.

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