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Could you help me solve some or all of the problems please? I can't understand the procedure for solving them...

solve the following problems determines algebraically the perimeter and area of the following questions

sorry if i did something wrong i'm new and i don't understand english very well enter image description here

Thank you for your attention, it would be a pleasure if you could answer my question

DanLewis3264
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Dr.Adri Aleksandr
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    In these perimeter and area questions, you are effectively being asked to add or multiply the dimensions together to get the resulting quantity. For example with a width of $3n$ and a height of $2n$ the resulting area would be $3n\cdot 2n=6n^2$ and the perimeter would be $3n+2n+3n+2n=10n$. – abiessu Oct 29 '20 at 15:51
  • ahhhhh I think I understand a little – Dr.Adri Aleksandr Oct 29 '20 at 15:52
  • thank you for everything – Dr.Adri Aleksandr Oct 29 '20 at 15:53
  • You're welcome. Feel free to edit the question or ask a new one if there is a more specific issue you encounter. – abiessu Oct 29 '20 at 15:54

1 Answers1

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Question 1

note that we know how to solve the area and perimeter of a rectangle, a square being a unique version of this solution. I.e. $A=Width * Height , P=2*Width + 2*Height$

Rectangle 1: (note that all squares are rectangles, so technically this is correct)

$p= 2*3m+2*3m = 6m+6m = 12m $ , $A = 3m*3m = 9m^2$

Rectangle 2:

$p= 2*2n+2*3m = 4n+6m$ , $A= 2n*3m $

Rectangle 3: $p=2*2n+2*2n=8n$ , $A=2n*2n = 4n^2$

Rectangle 4 (the large unmarked square) Is using the information on the previous examples to formulate the same type of answer (note that you could also use the expressions that we have created to calculate the perimeter and area, I shall use this way but it is worth you trying to form it like I did for the smaller squares to see if you get the same answer)

$P=\frac{r_1+2r_2+r_3}{2} = \frac{12m+2(4n+6m)+8n}{2} = \frac{24m+16n}{2} = 12m+8n$

$A=r_1+2r_2+r_3 = 9m^2+2(2n*3m)+ 4n^2 = 9m^2+(4n*6m)+4n^2$ $A=(3m+2n)^2$

I would suggest looking at the last "collection' of shapes to see if you can apply the same reasoning as I did for the first three. If you can, have a think why I was able to do it differently. I hope that answers your question

Sean
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