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$$ \int_0^h\!\exp\left( ity + (\alpha-1) \ln y \right)\,dy, $$ where $i = \sqrt{-1}$, $\alpha>0$, and $h>0$.

Please show your work step by step.

I know $$ \int\! \exp \left( mx \right)\,dx = \frac{\exp ( mx )}{m} + c, $$ where $c$ is a constant. So I have done : $$ \int\!\exp\left( ity + (\alpha-1) \ln y\right) dy = \frac{exp \left(ity + (\alpha-1) \ln y\right)}{it + (\alpha-1)\frac{1}{y}} $$ is this right?

Alternative method is not coming in my mind.

Stahl
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