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A company is selling 105 tickets to a plane that has 98 seats because only 85% of the buyers actually take the flight. What is the probability that even taking this approach 3 seats will be unused?

For me the sucess would be 15, the number of the sample 105 and the event would be 1, 2 and 3. But it seems its wrong.

Diego Alves
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1 Answers1

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The probability that exactly 3 seats will be unused is:

$$\binom{105}{95}0.85^{95}0.15^{10}$$

tommik
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