If R = $(\frac{V}{pi})^\frac{1}{3}$
If I ask you to find $R^2$.
We substitute it and make the power 2/3 as I saw in my textbook.
Why didn’t the powers add if they are multiplied.
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1$\frac{1}{3} + \frac{1}{3} = \frac{2}{3} = 2 \cdot \frac{1}{3}$ – AnalysisStudent0414 Nov 27 '20 at 12:58
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1/3 + 2 right ? – Nov 27 '20 at 12:59
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1That's not how it works. By elementary properties of exponentials, $(x^a)^b = x^{ab}$. – AnalysisStudent0414 Nov 27 '20 at 13:00
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Then when do powers add. – Nov 27 '20 at 13:01
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1$x^a \cdot x^b = x^{a+b}$ – AnalysisStudent0414 Nov 27 '20 at 13:01
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2The powers are not added but composed. – Bernard Nov 27 '20 at 13:01
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Ok .Thank you.Silly mistake. – Nov 27 '20 at 13:02