$$\frac{q^{n+1}-1+q^{n+1}(q-1)}{q-1}=\frac{q^{(n+1)+1}-1}{q-1}$$ I don't understand this step above, how can I get the right sight?
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Right-hand side seems to be $q^{(n+1)+1}-1$.
Wuestenfux
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Yeah a -1 is missing. – Measure me Nov 28 '20 at 15:23
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could eventually somebody text why is the calculation above correct? I'm not able to see it and it's frustrating me a lot. – Herrpeter Nov 28 '20 at 15:25
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$$\frac{q^{n+1}-1+q^{n+1}(q-1)}{q-1}=\frac{q^{n+1}-1+q^{(n+1)+1}-q^{n+1}}{q-1}$$ Then it equals the RHS, as the term $q^{n+1}$ cancels.
popping900
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