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** Prove that if for a number x ∈ R x + x ^(-1) ∈ Z , then for all n ∈ Z cases x^n + x^(−n) ∈ Z.strong text**

2 Answers2

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Induction hint: The cases $n=0$ and $n=1$ are trivial.

Suppose $x^{n-1} + x^{1-n}$ and $x^{n-2} + x^{2-n}$ are integers.

Consider the product $(x + x^{-1})(x^{n-1} + x^{1-n})$, and show that $x^n + x^{-n}$ must be an integer.

player3236
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  • +1 : After finding a kludgy solution associated with my first hint, I found a more elegant Fibonacci-like approach associated with my 2nd hint. Your approach is even more elegant. – user2661923 Nov 30 '20 at 12:21
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Hint

If $x + \frac{1}{x} = a$, then solve for $x$ in terms of $a$.

Then, prove the following lemma:

If $a$ is an integer and $b,n$ are a positive integers, then

$$(a + \sqrt{b})^n + (a - \sqrt{b})^n ~\text{is an integer}.$$

Hint-2

$$\left[a \times \frac{a \pm \sqrt{a^2 - 4}}{2}\right] ~-~ 1 ~=~ \left[\frac{a \pm \sqrt{a^2 - 4}}{2}\right]^2.$$

user2661923
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  • can i ask for a little more information? :))) – tom2563 Nov 30 '20 at 08:37
  • can i ask for a little more information? – tom2563 Nov 30 '20 at 08:38
  • @tom2563 Just providing you with these hints approached violating mathSE protocol. To say more would cross the boundary. See these links:https://math.meta.stackexchange.com/questions/9959/how-to-ask-a-good-question https://math.meta.stackexchange.com/questions/9959/how-to-ask-a-good-question#9960 https://math.meta.stackexchange.com/questions/9959/how-to-ask-a-good-question/27933#27933. Your query has already received two down votes because it did not meet the mathSE standard discussed in these links. You need to edit your query in accordance with these links. – user2661923 Nov 30 '20 at 08:41
  • ohh, im so sorry, im a beginner :(( – tom2563 Nov 30 '20 at 08:48
  • so solve for x with a its ready. and after? please help a little more – tom2563 Nov 30 '20 at 08:49
  • @tom2563 You have to edit your query to show that you have made a legitimate attempt to solve for $x$ in terms of $a$, discover the relationship between the problem and the lemma, and then prove the lemma. You do not have to succeed. But you do have to edit your query to show a serious attempt. – user2661923 Nov 30 '20 at 08:51