We want to find the maximum area of a triangle inscribed in a circle with radius r and with constant difference of two of its angles.
If $a, b, c$ are the angles of the triangle, if we set, wlog that $a>b$, we need to have:
$a-b = k$ (constant) and
$a+b+c=180$, so $a+b = 180-c$
I know that in general, without the restriction of the $2$ angles fixed difference, the largest triangle is the equilateral. Any assistance is much appreciated (by the way this is not homework or anything; just challenge between friends).