$$f(z)=\prod_{n=1}^{\infty}\left(1-\frac{z^2}{n^2}\right)-1$$
How many zeros does the above function have in $\Bbb{C}$?
$$f(z)=\prod_{n=1}^{\infty}\left(1-\frac{z^2}{n^2}\right)-1$$
How many zeros does the above function have in $\Bbb{C}$?
As noted in a comment, this is essentially the problem of determining the number of solutions to $\sin(z)=z$. There are infinitely many. It turns out more generally, as I learned from Aryabhata's answer at this link, with reference to an example in Markuševič's book at this link, that for every complex number $A$, the equation $\sin(z)=Az$ has infinitely many solutions in the complex plane.