I have a hard time understanding what the topology on CW-complexes is, i.e. what the open sets of a given CW-Complex $K$ or $n$-skeleton $K^{(n)}$ are.
From my understanding we get the topology inductively and we start with the discrete topology on the $0$-cells $K^{(0)}$.
Then we add the $1$-cells by taking the disjoint union with the $0$-cells and identifying the boundary of our $1$-cells with $0$-cells via the maps $f_\alpha: \partial D^1_{\alpha}\rightarrow K^{(0)}$.
And on $K^{(1)}$ we have the quotient topology. So this works for $n=1,2$ maybe $3$ but for general $n$ is there no easier way to determine whether a set is open in $K^{(n)}$ or not? An easier equivalent definition? Or is this actually easy already and i just don't really understand it? I guess my question is just this: what does it mean if $A \subset K^{(n)}$ is open?