I am going over the book "Optimization by Vector Space Methods" by Luenberger, and I found a statement that I'm not sure I understand. I am attaching the relevant page and I drew a box around the question in hand. I am not sure why the Gateux differential equals $\frac{d f(x+\alpha h)}{d \alpha}$ at $\alpha=0$ in the case the functional is real.
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By definition, $$ \delta f(x,h)=\lim\limits_{\alpha\to 0}\frac {f(x+\alpha h)-f(x)}{\alpha}=\lim\limits_{\alpha\to 0}\frac {f(x+\alpha h)-f(x+0h)}{\alpha} $$ which is by definition the derivative of the function $\alpha\to f(x+\alpha h)$ at $\alpha=0$.
GReyes
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Ha! Thanks :) I complicated it waaaay too much. – daniel Feb 11 '21 at 06:27
