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For a function $f(x)$, if I graph $f(2x)$, then it would look like $f(x)$ but compressed by a factor of $2$. If I graph $f(\frac{x}{2})$, then it would be stretched. I am very curious to know whether we can say something similar graphically about $f(ix)$, where $i = \sqrt{-1}$.

For instance for $\cosh(x),$ the graph looks like a parabola. However as soon as I scale it by a factor of $i$, the graph becomes a cosine curve(since $\cosh(ix) = \cos(x)$),completely looking different and having different properties from the original function. I am just curious to see whether there is a way to explain what happens when we scale a function by a factor of $i$, since it appears to be unpredictable. I would appreciate your help. Thanks.

Akil
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  • In a sense "yes" because there's only one analytic function that is equal to cosine on the real line, but I don't know how to give anything more specific – Calvin Khor Feb 13 '21 at 02:48

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