1

Let $X_t=Yt+Zt^2$ be random process, where $Y$,$Z$ are uncorrelated random variables, with characteristics: $EY=3$, $EZ=0.5$, $DY=1$, $DZ=0.05$. Find $X_t$ mean and covariance and prove whether process is wide-sense stationary.

Covariance:

$\Gamma(Y,Z)=E(YZ)-EYEZ=EYEZ-EYEZ=0$

How about its mean? Any hint?

1 Answers1

1

$\newcommand{\cov}{\operatorname{cov}}$

You've seen the answer to the first question in comments. As for covariance, you're making it unreasonably complicated. $$ \begin{align} \cov(X_t,X_s) & = \cov(Yt+Zt^2,Ys+Zs^2) = \cov(Yt,Ys+Zs^2)+\cov(Zt^2,Ys+Zs^2) \\[8pt] & =\cov(Yt,Ys)+\cov(Yt,Zs^2)+\cov(Zt^2,Ys)+\cov(Zt^2,Zs^2) \\[8pt] & = st\cov(Y,Y) + ts^2\cov(Y,Z) + t^2 s\cov(Y,Z) + t^2 s^2 \cov (Z,Z) \\[8pt] & = st\operatorname{var}(Y) + 0 + 0 + t^2s^2 \operatorname{var}(Z). \end{align} $$