I am looking for two closed subsets A and B (with $A\cap B = \emptyset$) of $\mathbb{R}$ with $d(A,B)=0$. I found a solution in $\mathbb{R}^2$, namely $A=\{(x,\frac{1}{x})\mid x>0\}$ and $B=\{(x,0)\mid x>0\}$. I know that those subsets have to be unbounded because there is a theorem that says: the distance between two closed subsets of which one is bounded, is greater than 0.
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Set $A=\mathbb{N}\setminus \{1\}$ and $B=\{x+\frac{1}{x}:x\in A\}$
vadim123
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Isn't ${x:x\in T}$ simply $T$? – celtschk May 28 '13 at 16:21
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@celtschk, okay, if you like. – vadim123 May 28 '13 at 16:22
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I used one of your sets to give another example: $$A=\{(x,y)\mid xy\ge -1,x<0\},~~B=\{(x,y)\mid xy\ge1,x>0\}$$

Mikasa
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