The total number of prime factors of this number: $2^{22}$ x $7^5$ x $11^2$
Should be only 3, which are 2, 7 and 11 itself. However the answer states that there are total $(22+5+2) = 29$ prime factors. What? How?
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3You answer to the question "what is the total number of distinct prime factors of this expression?". They answer to the question in the title. – Raskolnikov Mar 21 '21 at 06:13
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When you are asked
How many prime factors does the number $n$ have?
this doesn't mean
How many factors / divisors does $n$ have that are prime?
which is what you answered, but rather
If you write $n$ as a product of primes, how many factors do you get?
In this case we get twenty-two 2's, five 7s and two 11s for a total of 29.
Arthur
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