Let $V$ be a $k$-vectorial space of finite dimension $n$, every subspace $U \subseteq V$, can be seen as a direct summand of $V$, it is sufficient choose a basis of $U$ and by completing to a basis of $V$, the elements that don't belong to the basis of $U$, generate a subspace $U'$ such that $U \oplus U'=V$. My question is: is this also true when $V$ is an infinite dimensional vectorial space?
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Sure, if you're comfortable with the axiom of choice. See https://math.stackexchange.com/a/383778/732532 and https://math.stackexchange.com/a/3737093/732532. – morrowmh Mar 21 '21 at 17:46
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Thank you very much!! – Rick88 Mar 21 '21 at 17:51
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The existence of a basis for any infinite-dimensional vector spaces is equivalent to Zorn's lemma and the Axiom of Choice. So "yes", if you accept AC, and "it depends", if you don't.
Tristan Duquesne
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