Let $f_\theta (x) = \theta x^{\theta-1}$, where $0<x<1$, $x_1, x_2$ are iid
Find $P(x_1x_2 \geq 0.75)$
I used double integration to obtain the joint probablity,
$$\begin{align*}
P(x_1x_2 \geq 0.75) &= \int_{0.75}^1 \theta x_1^{\theta - 1} \int_{0.75/x_1}^1 \theta x_2^{\theta - 1} dx_2 dx_1 \\
&= \dots \text{skip the steps of integration} \\
&= 1 - 0.75^\theta + 0.75^\theta \cdot ln0.75
\end{align*}$$
However, refer to For the density function $f_\theta (x) = \theta x^{\theta-1}$, how can we find the product distribution, $\prod_{i=1}^n X_i$?
Should $P(x_1x_2 \geq 0.75) = P(Gamma(2,\theta) \geq 0.75)$?
The answers are different using two approaches.
Update
I think I got it,
$$\begin{align*}
P(x_1x_2 \geq 0.75) &= P(exp(-Gamma(2,\theta)) \geq 0.75) \\
&= P(Gamma(2,\theta) \leq -ln0.75)
\end{align*}$$
Is this right?
