Real analysis question. Having trouble either coming up with a counterexample where the sum would be continuous at a, or proving that the sum would be discontinuous at a for all cases.
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Consider $f(x)=1/x, g(x)=-1/x$ and their sum at $x=0$. – user Mar 26 '21 at 16:01
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Take any fonction $f$ that is discontinuous at a point $x$. Then so is $g = -f$. But $f+g = 0$ is continuous everywhere.
Didier
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Pick $$f(x)= \begin{cases}1 & \text{if } x \neq 0, \\ 0 & \text{if } x =0. \end{cases}$$
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$$g(x)= \begin{cases}0 & \text{if } x \neq 0, \\ 1 & \text{if } x =0. \end{cases}$$
Son Gohan
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