I can't give a proof of this fact: "Given a non-empty set $X$ and an equational class $V$, then $V$ contains a free object on $X$." $V$ is a class of algebras of a certain language of algebras $L$ and $V$, qua equational class, is $M(\Sigma)$ where $\Sigma$ is a set of identities and $M(\Sigma))$ indicates the class of $L$-algebras satisfying $\Sigma$. I wanna show that the couple $((W_{X},\Sigma),F)$ is an $L$-algebra, where $W_{X}$ is the set of words in the alphabet $X$ and with the only relations between words are given by $\Sigma$ and $F$ is the set of operations on $W_{X}$ given by the language $L$. The problem is: how to define $F$? Is this the right way to prove this fact? I don't know much about cathegory theory so I am trying this way.
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2)If $p_{1},...,p_{n} \in T(X)$ and $f \in L_{n}$ then $f(p_{1},...,p_{n}) \in T(X)$. Now I define an identity of type $L$ on $X$ as an ordered pair $(p,q)$, where $p,q \in T(X)$. Now the free object on X in the language $L$ is the pair $(W,F)$ where $W$ is the set of words on T(X) with relations given by $\Sigma$ and operations are "just strings".
– SilvioM Mar 29 '21 at 15:03