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This is from 2012 Euclid. I was wondering if someone could point out the flaw in my reasoning here: Let the minute hand point to $50+x$ minutes. Then the hour hand points to $45 + \dfrac{50 + x}{12}$ minutes because the hour hand moves at a rate 1/12 that of the minute hand. Since the hour hand will move from $45 + \dfrac{50 + x}{12}$ to $50+x$ the number of minutes it travels is

$50+x -45 - \dfrac{50 + x}{12} = \dfrac{11x + 10}{12}$

but since the minute hand travels to $45 + \dfrac{50+x}{12}$ and the hour travels to $50+x$ we know that

x = $\dfrac{45 + \dfrac{50+x}{12}}{12}$ and

x = $\dfrac{590}{143}$

Plugging this into $\dfrac{11x + 10}{12}$ we get 60/13 and we divide by 12 to convert minutes to hours, for a total of 5/13 hours. The correct answer is 12/13. I was hoping someone could point out the error in my solution, rather than providing a new one, as I have seen better ways to solve this using angles, but would like to see the error here.

yvngyup
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2 Answers2

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Your calculation of $x$ is correct, and you are correct to conclude that the hour hand has moved $60/13$ minute marks from start to finish. But the hour hand moves $5$ minute marks per hour, so to obtain hours elapsed you should divide $60/13$ by $5$ (rather than divide by $12$), obtaining $12/13$ hours elapsed.

grand_chat
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there are 60 minutes in hour. So, the minute hand moves 12 times as quickly as the hour hand,so 60-x/x=12 or x=60/13 ---> eq.(1) In one hour, the hour hand moves through 1/12 x 60 = 5. Since the hour hand is moving for t hours, then 5t = x Substitute value of x from eq.1 5t = 60/13 t = 12/13

Maverick
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