I was trying to simplify the solution, $\frac{1}{5}(1+2\sqrt[3]{2}-2^{2/3})$, from a problem I done and saw that mathematica suggested $\frac{1}{1+2^{2/3}}$. I was wondering if anyone could show how to approach simplification of such expressions manually (it appears to amount to the step in the title of the post)?
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This is the cubic formula from basic algebra:
$$a^3+b^3=(a+b)(a^2-ab+b^2)$$
$$\frac{a^3+b^3}{a+b}=a^2-ab+b^2$$
Observe,
$$\begin{align}(1+2^{2/3})×(1+2\sqrt[3]{2}-2^{2/3})&=1^3+2^2\\ &=5.\end{align}$$
lone student
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Ah, that's lovely - thanks a lot! – A quarky name Apr 12 '21 at 11:20
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@Aquarkyname You're welcome. – lone student Apr 12 '21 at 18:35