One morning each member of Angela's family drank an 8-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family?
Let $c$ and $m$ denote the total amount of coffee and milk, respectively, in ounces. Then we have the linear system of equations:
$\frac{c}{6} + \frac{m}{4} = 8, \tag1$
$c + m = 8n. \tag2$ Multiplying equation (1) above by $(12)$ gives
$2c + 3m = 96\tag3$ How can I reduce the system to just a one-variable equation solving for $n$? I've tried to manipulate and use substitution in a variety of ways but my experiments don't get me anywhere. I'm just lost/confused at this point.
The problem gave this hint "Let $c$ be the amount of coffee Angela drank, $m$ be the amount of milk she drank, and $n$ be the number of people in the family, Write two equations based on the information in the problem. Slove for $n$ in terms of $c$.
I found letting $c$ be the total amount of coffee and $m$ being the total amount of milk more intuitive. I couldn't figure out the equation for $8n$ otherwise.
The question Find the number of members of a family is similar but the answer presented a formula I haven't studied yet, I'm still on basic algebra.