If $f$ is a holomorphic function on a simply connected open domain $\Omega$, and $f$ is a linear function on the boundary $\Omega$, i.e. $f=az+b$ on $\partial\Omega$. Then, can I say that $f$ is also linear function on $\Omega$?
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Since $f(z)=az+b$ on the boundary, we know $g(z):=f(z)-az-b=0$ on $\partial \Omega$. By the maximum modulus principle, $g(z)=0$ for all $z\in\Omega$, or equivalently, $f(z)=az+b$.
Clayton
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Thanks, Clayton. It is very helpful and clear. – David Jun 04 '13 at 03:30