The problem reads like this: The number of calls the company receives is 4 per hour. a) Find probability to get exactly 5 between 09:00 and 12:00 of a given day
b) Given that there the company has received at least 6 between 12:00-14:00, what is the probability to get 8 calls for the same period?
c) For a week of 7 days, what is the probability of having 4 days when there are not phone calls between 12:30-13:00?
For a) I already know $P(x=5, \lambda=2\cdot4=8 ) = \frac{8^5 e^{-8}}{5!}$.
However, I am not sure what needs to be done for b) and c)... For b) I guess needs something like
$P(x\ge 8) = 1- P(x=6) - P(x=7)$ ?
But then, it does not give any clue about the numerical values of $P(x=6), P(x=7)$ so I conclude the given information has to be combined in another way.
And c, is a complete mystery, so any hint would be much appreciated!.