If $(8x+1), (6x-1)$ and $(3x+5)$ are in an AP, find the value of $x$. This sum is from a question paper and there is no other information given. I was able to solve other sums which had more information available. But I'm stuck at this sum.
Asked
Active
Viewed 82 times
-2
-
2There is sufficient information, what have you tried so far? What do you know of arithmetic progressions? – Macavity Jun 04 '21 at 09:45
-
2Edit and include your efforts, please. – Ritam_Dasgupta Jun 04 '21 at 09:45
-
@Macavity The formulas I have been taught require either the first term of an AP or the difference or at least the sum/product of all terms in the AP. However, this is the only question that is different and I have no idea how to approach this problem. – NAPOLEON039 Jun 04 '21 at 09:49
-
Well, you have two ways to express the common difference from the information given, try it and edit the post above. if you still need help, i am sure you'll get it here. – Macavity Jun 04 '21 at 09:51
-
Here is the solution: https://brainly.in/question/14434359 – Jun 04 '21 at 10:02
1 Answers
1
In an A.P, $$a_2-a_1=a_3-a_2$$ Here $a_1=8x+1, a_2=6x-1, a_3=3x+5$ So, $$(6x-1)-(8x+1) = (3x+5)-(6x-1)$$ $$\implies6x-1-8x-1=3x+5-6x+1$$ $$\implies-2x-2=-3x+6$$ $$\implies x=8$$ Therefore the value of $x$ is $8$
Hope it helps
p_square
- 1,007
- 1
- 6
- 23
-
1
-
@Saad I apologize for posting a question with so few details, but I really had no other information available and could not infer more from the problem statement. This is not to say there is a problem with the sum, but a problem with my ability to solve math.
I will try my best to improve and add more information to my questions in the future
– NAPOLEON039 Jun 04 '21 at 11:36 -
-
@NAPOLEON039 This time I answered your question but from next time please make sure that you also add what you have done to solve this problem :) – p_square Jun 04 '21 at 11:58
-