$$f(x)=\begin{cases} 0 & |x|\leq \frac{\pi}{2}\\ 3 & \frac{\pi}{2}<|x|\leq \pi \end{cases}$$
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2would be great to have your thoughts and attempts. In particular, do you have any partucular doubt that prevents you from completing the task? – Siong Thye Goh Jun 04 '21 at 09:54
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Consider cases with respect to absolute value. – zkutch Jun 04 '21 at 09:56
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Hey guys, thanks for comments. This is what I tried: https://prnt.sc/13zrm3i – benzi Jun 04 '21 at 09:59
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It seems you got it right, maybe just add semi-circles to identify strict inequalities and filled circles for loose inequalities to the ends of the segments and it will be perfect.(e.g. https://math.stackexchange.com/a/2423560/399263) – zwim Jun 04 '21 at 10:05
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@zwim Thank you very much! – benzi Jun 04 '21 at 10:31
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Your graph is correct though I think it's good to highlight what value is taken when $|x|=\frac{\pi}2$.
However, what you wrote at the side is not correct.
$$\frac{\pi}{2}<|x|\le \pi$$
consists of two regions, $-\pi \le x < -\frac{\pi}2$ and $\frac{\pi}2 < x \le \pi$.
Siong Thye Goh
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