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From what I understand, an equivalence relation is a relation which must be

  • reflexive
  • symmetric
  • transitive

The relation in question is:

  • reflexive because the square of a number is always positive
  • symmetric as $xy=yx$
  • transitive as if $xy>0$ and $yz>0$, then $xy^2z>0$. Divide the last expression by $y^2$, and we find that $xz>0$
csmathhc
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1 Answers1

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$0^2$ is not positive, so the relation is not reflexive.

Pomponazzo
  • 2,003