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How would you begin to solve this?

Do you use $A = 4\pi r^2$?

$V = \frac43\pi r^3$.

Substitute $180$ for $A$, solve for $r$ and plug into Volume equation(leave in simplified form).

amWhy
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2 Answers2

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Using the formulas: $$A = 4 \pi r^2$$ and $$V = \frac43 \pi r^3$$ We get that $$V = \frac{A^{\frac32}}{6\sqrt{\pi}}\tag{Quite a known formula}$$ Substitute the values of $A$ and you get: $$\frac{180^{\frac32}}{6\sqrt{\pi}} \approx 227.081$$

Hope it helps :)

p_square
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Another way is to notice that $A^3 = 64 \pi^3 r^6$ and $V^2 = \frac{16}{9} \pi^2 r^6$.

Therefore

$$\frac{V^2}{A^3} = \frac{1}{36 \pi}$$ and $$V = \frac{A^{3/2}}{6 \sqrt \pi} \approx 227.1$$

Which avoids to solve $r$ from $A$.