Looking my professor steps to simplify a boolean expression, he went from
$$A'(B+C)(A+B)C'+B'$$
to
$$A'(B+C)BC'+B'.$$
I've been trying to understand how did he do that but I can't. Can anyone help me clarify how this step was done?
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What does the slash mean? – amrsa Jul 03 '21 at 19:03
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Negation, sorry but it's simillar to A' – Lucas Brodersen Jul 03 '21 at 19:05
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1Then just use distributivity, and the fact that $A'A=0$, where $A'$ is the negation of $A$. – amrsa Jul 03 '21 at 19:06
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Ouch, true, omg ty – Lucas Brodersen Jul 03 '21 at 19:07
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I've upvoted your question as a courtesy for being your first one. Next time, consider to type it with MathJax. – amrsa Jul 03 '21 at 19:09
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Certainly Amrsa, thanks a lot – Lucas Brodersen Jul 03 '21 at 19:38
1 Answers
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Simply by using distributivity. Indeed $$ A'(B+C)(A+B)C'= A'(B+C)AC' + A'(B+C)BC' $$ But now $A'A= 0$, so you can now easily conclude.
J.-E. Pin
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